Episode 8 — Aptitude and Reasoning / 8.12 — Problems on Trains

8.12 Quick Revision -- Problems on Trains

The Master Rule

    +-----------------------------------------------------+
    |                                                     |
    |  Time = (Sum of relevant lengths) / Relative speed  |
    |                                                     |
    +-----------------------------------------------------+

What Distance to Use

    +-------------------------------------------------------+
    | Scenario                    | Distance                 |
    |-----------------------------|--------------------------|
    | Train crosses pole/man      | L_train                  |
    | Train crosses platform      | L_train + L_platform     |
    | Train crosses bridge/tunnel | L_train + L_bridge       |
    | Two trains cross each other | L_train1 + L_train2      |
    | Train crosses man on        |                          |
    |   another train             | L_crossing_train ONLY    |
    | Man on train sees platform  | L_platform ONLY          |
    +-------------------------------------------------------+

What Speed to Use

    +-----------------------------------------------+
    | Scenario              | Relative Speed         |
    |-----------------------|------------------------|
    | Stationary object     | S_train                |
    | Same direction        | |S1 - S2|              |
    | Opposite direction    | S1 + S2                |
    +-----------------------------------------------+

Unit Conversion (Must Memorize)

    km/h to m/s:  x 5/18
    m/s to km/h:  x 18/5

    36 km/h = 10 m/s      72 km/h = 20 m/s
    54 km/h = 15 m/s      90 km/h = 25 m/s
    108 km/h = 30 m/s

Key Formulas

    1. Pole:       T = L / S
    2. Platform:   T = (L + P) / S
    3. Two trains: T = (L1 + L2) / S_relative
    4. Man on train sees other train: T = L_other / S_relative

Two-Equation Shortcut

    Crosses pole in T1, platform (length P) in T2:
    Speed = P / (T2 - T1)
    Length = Speed x T1

"Man on Train" Trap

    "Train crosses a man"        --> Distance = Train length ONLY
    "Two trains cross each other" --> Distance = BOTH lengths added

    This is the #1 most tested distinction!

Opposite vs Same Direction

    OPPOSITE:  Faster crossing (SUM of speeds)
    SAME:      Slower crossing (DIFFERENCE of speeds)

    Opposite direction crossing time is always LESS than
    same direction crossing time for the same trains.

Fence-Post Rule

    n poles = (n - 1) gaps

    Distance = (n - 1) x gap_length

Speed Reasoning Checklist

    [ ] Convert km/h to m/s FIRST
    [ ] Identify WHAT crosses WHAT
    [ ] Determine total distance (train length? both lengths? platform?)
    [ ] Determine direction (same or opposite?)
    [ ] Calculate relative speed
    [ ] Apply T = Distance / Speed
    [ ] Convert answer back if needed (seconds to minutes, m/s to km/h)

Common Mistakes

    1. Forgetting to add train length to platform length
    2. Using SUM instead of DIFFERENCE for same direction (or vice versa)
    3. Mixing km/h and m/s in the same equation
    4. Adding both lengths when a man (point) is the observer
    5. Forgetting fence-post counting (n posts = n-1 gaps)

Part of Section 8.12: Problems on Trains