Episode 8 — Aptitude and Reasoning / 8.22 — Syllogism
8.22.c Solved Examples -- Syllogism
Example 1: All + All Chain
Statements:
- All dogs are animals.
- All animals are living things.
Conclusions: I. All dogs are living things. II. Some living things are dogs.
Solution:
Step 1: Identify types. P1: All dogs are animals (Type A). P2: All animals are living things (Type A).
Step 2: Draw Venn diagram.
+-------------------------+
| Living Things |
| +------------------+ |
| | Animals | |
| | +------------+ | |
| | | Dogs | | |
| | +------------+ | |
| +------------------+ |
+-------------------------+
Step 3: Test conclusions.
- I. All dogs are living things -> Dogs is inside Living Things. TRUE.
- II. Some living things are dogs -> Since dogs exist inside living things, at least some living things are dogs. TRUE.
Answer: Both I and II follow.
Example 2: All + No Chain
Statements:
- All roses are flowers.
- No flower is a thorn.
Conclusions: I. No rose is a thorn. II. Some thorns are roses.
Solution:
Step 1: P1: All A are B. P2: No B is C. Chain: All+No = No A is C.
Step 2: Venn diagram.
+----------+ +----------+
| Flowers | | Thorns |
| +------+ | | |
| | Roses| | | |
| +------+ | | |
+----------+ +----------+
Step 3: Test.
- I. No rose is a thorn -> Roses is inside Flowers, Flowers is separate from Thorns. TRUE.
- II. Some thorns are roses -> Thorns and Roses are completely separate. FALSE.
Answer: Only I follows.
Example 3: Some + All Chain
Statements:
- Some cats are black.
- All black things are dark.
Conclusions: I. Some cats are dark. II. All cats are dark.
Solution:
Step 1: P1: Some A are B (Type I). P2: All B are C (Type A). Chain: Some+All = Some A are C.
Step 2: Venn diagram.
+-----------------------+
| Dark |
| +---------+ |
| | Black | |
+--+--+------+----------+
| Cats| XX |
+-----+------+
XX = cats that are black (and therefore dark)
Step 3: Test.
- I. Some cats are dark -> Those cats that are black are also dark. TRUE.
- II. All cats are dark -> Some cats may NOT be black, hence not necessarily dark. FALSE.
Answer: Only I follows.
Example 4: No Definite Conclusion (Some + Some)
Statements:
- Some apples are red.
- Some red things are balls.
Conclusions: I. Some apples are balls. II. No apple is a ball.
Solution:
Step 1: P1: Some A are B. P2: Some B are C. This is the Some+Some case -> NO definite conclusion.
Step 2: Multiple Venn diagrams:
Diagram 1 (A and C overlap): Diagram 2 (A and C separate):
+----+----+----+ +----+---+---+----+
| A | AB | B | | A |AB | BC| C |
+----+--+-+--+-+ +----+---+---+----+
| BC |
+--+-+----+
| C |
+------+
In Diagram 1, some apples could be balls. In Diagram 2, no apple is a ball.
Step 3: Neither conclusion follows in ALL diagrams.
Step 4: Check Either-Or: "Some apples are balls" (I) and "No apple is a ball" (E) are complementary! At least one MUST be true.
Answer: Either I or II follows.
Example 5: Universal Negative Premise
Statements:
- No man is a machine.
- All machines are useful.
Conclusions: I. No man is useful. II. Some useful things are not men.
Solution:
Step 1: P1: No A is B. P2: All B are C.
Step 2: Venn diagram.
+-----------+ +-------------------+
| Men | | Useful |
| | | +-----------+ |
| | | | Machines | |
| | | +-----------+ |
+-----------+ +-------------------+
But wait -- Men and Useful might or might not overlap (since Useful is bigger than Machines):
Diagram 1: Men and Useful separate Diagram 2: Men and Useful overlap
+-----+ +-----------+ +----------+---------+
| Men | | Useful | | Men | Useful |
+-----+ | +-------+ | +----+-----+-+-------+
| |Machines| | |Machines|
| +-------+ | +--------+
+-----------+
Step 3: Test.
- I. No man is useful -> In Diagram 2, men can overlap with Useful. FALSE (not in all diagrams).
- II. Some useful things are not men -> Machines are useful and not men (No man is machine). TRUE in all diagrams.
Answer: Only II follows.
Example 6: Particular Negative
Statements:
- All pens are books.
- Some books are not pencils.
Conclusions: I. Some pens are not pencils. II. Some books are pens.
Solution:
Step 1: P1: All A are B (Type A). P2: Some B are not C (Type O).
Step 2: Venn diagram:
+------------------+
| Books |
| +------+ | +----------+
| | Pens | X | | Pencils |
| +------+ | | |
+---------+--------+-----+----------+
(Some books not pencils = X region)
The "X" (books not pencils) might or might not include pens.
Step 3: Test.
- I. Some pens are not pencils -> The "books not pencils" region might or might not include pens. Cannot be determined. Could be true, could be false. Does NOT follow.
- II. Some books are pens -> Since all pens are books, at least some books are pens. TRUE (conversion of All A are B gives Some B are A).
Answer: Only II follows.
Example 7: Three Premises
Statements:
- All A are B.
- All B are C.
- No C is D.
Conclusions: I. No A is D. II. All A are C. III. Some C are B.
Solution:
Step 1: Chain: All A are B + All B are C -> All A are C. Then: All A are C + No C is D -> No A is D.
Step 2: Venn diagram.
+----------------------------------+ +--------+
| C | | D |
| +------------------------+ | | |
| | B | | | |
| | +---------------+ | | | |
| | | A | | | +--------+
| | +---------------+ | |
| +------------------------+ |
+----------------------------------+
Step 3: Test.
- I. No A is D -> A is inside C, C is separate from D. TRUE.
- II. All A are C -> A inside B inside C. TRUE.
- III. Some C are B -> B is inside C, so some C are B. TRUE.
Answer: All three (I, II, III) follow.
Example 8: Either-Or with Type A and O
Statements:
- Some girls are students.
- Some students are tall.
Conclusions: I. All girls are tall. II. Some girls are not tall.
Solution:
Step 1: Some+Some -> No definite conclusion about girls and tall.
Step 2: Check Either-Or.
- I: "All girls are tall" (Type A)
- II: "Some girls are not tall" (Type O)
- Same terms (girls, tall), one is Type A, other is Type O -> Complementary pair!
Step 3: At least one must be true.
Answer: Either I or II follows.
Example 9: All-All with Reverse Conclusion
Statements:
- All teachers are graduates.
- All graduates are educated.
Conclusions: I. All teachers are educated. II. All educated people are teachers. III. Some educated people are teachers.
Solution:
+---------------------------+
| Educated |
| +-------------------+ |
| | Graduates | |
| | +------------+ | |
| | | Teachers | | |
| | +------------+ | |
| +-------------------+ |
+---------------------------+
- I. All teachers are educated -> Teachers inside Educated. TRUE.
- II. All educated are teachers -> Educated is bigger than Teachers. FALSE.
- III. Some educated are teachers -> Teachers exist inside Educated. TRUE.
Answer: I and III follow.
Example 10: No + No = No Conclusion
Statements:
- No car is a bus.
- No bus is a train.
Conclusions: I. No car is a train. II. Some trains are not cars.
Solution:
Step 1: No+No = No definite conclusion. (Two negative premises.)
Step 2: Venn diagrams:
Diagram 1: Car and Train separate Diagram 2: Car and Train overlap
+-----+ +-----+ +-------+ +-----+ +-----+
| Car | | Bus | | Train | | Car=Train| Bus |
+-----+ +-----+ +-------+ +---------+ +---+
- I. No car is a train -> True in Diagram 1, False in Diagram 2. Does NOT follow.
- II. Some trains are not cars -> True in Diagram 1, could be False if Car=Train in Diagram 2. Does NOT follow.
Step 3: Check Either-Or between I and II -> Not a complementary pair (I is "No A is C", II is "Some C are not A" -- different types, different terms order).
Answer: Neither I nor II follows.
Example 11: Some-No Chain
Statements:
- Some kings are queens.
- No queen is a prince.
Conclusions: I. Some kings are not princes. II. No king is a prince.
Solution:
Step 1: Some A are B + No B is C -> Some A are not C.
Step 2: Venn diagram:
+------+---+------+ +---------+
| Kings|KQ | Queens| | Princes |
+------+---+------+ +---------+
Kings that are queens cannot be princes (since no queen is prince). But other kings might or might not be princes.
- I. Some kings are not princes -> Those kings that are queens cannot be princes. TRUE.
- II. No king is a prince -> Some kings (not queens) might be princes. Does NOT follow.
Answer: Only I follows.
Example 12: Conversion Check
Statements:
- All poets are dreamers.
- No dreamer is a realist.
Conclusions: I. No poet is a realist. II. No realist is a poet. III. Some dreamers are poets.
Solution:
+-------------+ +------------+
| Dreamers | | Realists |
| +---------+ | | |
| | Poets | | | |
| +---------+ | | |
+-------------+ +------------+
- I. No poet is a realist -> Poets inside Dreamers, Dreamers separate from Realists. TRUE.
- II. No realist is a poet -> Same reasoning. TRUE. (No A is B implies No B is A.)
- III. Some dreamers are poets -> Poets exist inside Dreamers. TRUE.
Answer: All three follow.
Example 13: "Most" and "Few" Translation
Statements:
- Most birds can fly.
- All things that fly have wings.
Conclusions: I. Some birds have wings. II. All birds have wings.
Solution:
Step 1: "Most birds can fly" = "Some birds can fly" (Type I in logic).
Step 2: Some A are B + All B are C -> Some A are C.
+----------------------------+
| Have Wings |
| +------------------+ |
| | Can Fly | |
+--+--+--+------------+-----+
| Birds |XXXX|
+--------+----+
- I. Some birds have wings -> Those birds that fly have wings. TRUE.
- II. All birds have wings -> Not all birds fly (only "most"). Does NOT follow.
Answer: Only I follows.
Example 14: Possibility-Based Question
Statements:
- All roses are flowers.
- Some flowers are red.
Conclusions: I. Some roses are red. II. All roses being red is a possibility.
Solution:
Step 1: All A are B + Some B are C -> No definite conclusion about A and C.
Step 2:
Diagram 1 (roses and red overlap): Diagram 2 (roses and red separate):
+-------------------+ +-------------------+
| Flowers | | Flowers |
| +------+ +-----+ | | +------+ +-----+ |
| | Roses| | Red | | | | Roses| | Red | |
| | +---+--+--+ | | | +------+ +-----+ |
| | | X | | | | | +-------------------+
| +--+---+ +--+--+ |
+-------------------+
- I. Some roses are red -> Not true in all diagrams. Does NOT follow (as a definite conclusion).
- II. All roses being red is a possibility -> In some valid diagram, all roses can be inside red. TRUE (as a possibility).
Answer: Only II follows.
Example 15: Three-Circle Problem
Statements:
- Some A are B.
- All B are C.
- No C is D.
Conclusions: I. Some A are C. II. Some A are not D. III. No B is D.
Solution:
Step 1: From P1+P2: Some A are B, All B are C -> Some A are C. From P2+P3: All B are C, No C is D -> No B is D. From "Some A are C" + P3: Some A are C, No C is D -> Some A are not D.
+------------------+ +--------+
| C | | D |
| +----------+ | | |
| | B | | | |
+--+--+--+----+----+ +--------+
| A |XX|
+-----+--+
- I. Some A are C -> TRUE.
- II. Some A are not D -> TRUE.
- III. No B is D -> B inside C, C separate from D. TRUE.
Answer: All three follow.
Example 16: Tricky "Some Not" Problem
Statements:
- All A are B.
- Some B are not C.
Conclusions: I. Some A are not C. II. Some B are A.
Solution:
Step 1: P1 is All A are B. P2 is Some B are not C. The "Some B not C" may or may not include any A.
Diagram 1: A overlaps with "B not C" Diagram 2: A is entirely within "B and C"
+------------------+ +------------------+
| B | | B |
| +-----+ +----+ | | +----+-----+ |
| | A | | C | | | | C | A | |
| | (not C) +----+ | | +----+--+--+ XX |
| +-----+ | | (XX=B not C)
+------------------+ +------------------+
- I. Some A are not C -> True in Diagram 1, False in Diagram 2. Does NOT follow.
- II. Some B are A -> Since All A are B, conversion gives Some B are A. TRUE.
Answer: Only II follows.
Example 17: Complete Overlap Possibility
Statements:
- All dogs are pets.
- All cats are pets.
Conclusions: I. Some dogs are cats. II. No dog is a cat.
Solution:
Diagram 1: Dogs and cats overlap Diagram 2: Dogs and cats separate
+------------------------+ +------------------------+
| Pets | | Pets |
| +------+---+------+ | | +------+ +------+ |
| | Dogs | X | Cats | | | | Dogs | | Cats | |
| +------+---+------+ | | +------+ +------+ |
+------------------------+ +------------------------+
- I. Some dogs are cats -> True in D1, False in D2. Does NOT follow.
- II. No dog is a cat -> True in D2, False in D1. Does NOT follow.
Step 3: I (Type I) and II (Type E) with same terms -> Complementary pair!
Answer: Either I or II follows.
Example 18: Reverse Direction
Statements:
- No pen is an eraser.
- All erasers are rubber.
Conclusions: I. No pen is rubber. II. Some rubber things are not pens. III. Some rubber things are erasers.
Solution:
+---------+ +----------------+
| Pens | | Rubber |
| | | +----------+ |
| | | | Erasers | |
| | | +----------+ |
+---------+ +----------------+
(Pens may or may not overlap with Rubber, but not with Erasers)
- I. No pen is rubber -> Pens might overlap with the non-eraser part of Rubber. Does NOT follow.
- II. Some rubber things are not pens -> Erasers are rubber and not pens. TRUE.
- III. Some rubber things are erasers -> All erasers are rubber. TRUE.
Answer: II and III follow.
Example 19: Four Conclusions
Statements:
- Some stars are planets.
- All planets are celestial.
Conclusions: I. Some stars are celestial. II. All stars are celestial. III. Some celestial things are planets. IV. Some celestial things are stars.
Solution:
From P1+P2: Some stars are planets, All planets are celestial -> Some stars are celestial. From P2 conversion: All planets are celestial -> Some celestial are planets.
+---------------------+
| Celestial |
| +------------+ |
| | Planets | |
+--+----+--+----+-----+
| Stars |XX|
+-------+--+
- I. Some stars are celestial -> TRUE.
- II. All stars are celestial -> Not all stars are necessarily planets. Does NOT follow.
- III. Some celestial things are planets -> TRUE (conversion of P2).
- IV. Some celestial things are stars -> TRUE (conversion of conclusion I).
Answer: I, III, and IV follow.
Example 20: All Four Statement Types
Statements:
- All A are B.
- No B is C.
- Some C are D.
Conclusions: I. No A is C. II. Some D are C. III. Some D are not B.
Solution:
From P1+P2: All A are B + No B is C -> No A is C. From P2+P3: No B is C + Some C are D -> Some D are not B (via Some C are D, those C are not B, so those D that are C are not B). Actually: From P3 conversion: Some C are D -> Some D are C. From P2: No B is C -> No C is B. Combined with Some C are D: Some D (that are C) are not B.
+--------+ +----------+---+--------+
| B | | C |CD | D |
| +----+ | | +---+ |
| | A | | | |
| +----+ | +-----------------------+
+--------+
- I. No A is C -> TRUE.
- II. Some D are C -> Conversion of P3. TRUE.
- III. Some D are not B -> D that are C cannot be B (since No B is C). TRUE.
Answer: All three follow.
Example 21: Edge Case -- Same Terms
Statements:
- All mangoes are fruits.
- All fruits are mangoes.
Conclusions: I. All mangoes are fruits. II. All fruits are mangoes.
Solution:
Both premises together mean Mangoes = Fruits (identical sets).
+--------------+
| Mangoes = |
| Fruits |
+--------------+
- I. All mangoes are fruits -> TRUE (given directly).
- II. All fruits are mangoes -> TRUE (given directly).
Answer: Both I and II follow.
Example 22: The "At Least" Interpretation
Statements:
- Some boys are tall.
- Some tall people are strong.
- All strong people are healthy.
Conclusions: I. Some boys are healthy. II. Some tall people are healthy.
Solution:
From P2+P3: Some tall are strong + All strong are healthy -> Some tall are healthy. From P1+P2: Some boys are tall + Some tall are strong -> Some+Some = No definite conclusion about boys and strong.
+-------------------+
| Healthy |
| +----------+ |
| | Strong | |
+--+---+--+---+----+
| Tall |XX|
+--+---+--+
|Boys|YY|
+----+--+
- I. Some boys are healthy -> Cannot chain Some+Some. Does NOT follow.
- II. Some tall people are healthy -> From P2+P3 chain. TRUE.
Answer: Only II follows.
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